Als
f : x → x + 1   en
g : x → x ²
dan beeldt
(fog − gof)
x   af in  ?
A.  − 1
B.  1
C.  0
D.  2x + 1
E.  − 2x
                 

[ 3-8382 - op net sinds 17.6.2020-(E)-24.10.2023 ]

Translation in   E N G L I S H

IN CONS
IN CONSTR
IN CONSTRUC
IN CONSTRUCTI
IN CONSTRUCTION
A.  
B.  
C.  
D.  
E.  

Oplossing - Solution

(fog)(x) = f(g(x)) = f(x²) = x² + 1
(gof)(x) = g(f(x)) = g(x+1) = (x + 1)² = x² + 2x + 1
(fog)(x) − (gof)(x) = x² + 1 − (x² + 2x + 1) = − 2x