Wiskunde Multiple Choice Vraag uit Gricha's Wiskundige Vragenbank

$\frac{(a-b)^2}{a^2-b^2}$ is gelijk aan	A. 1
	B. − 2ab
	C. \(\frac {a\,-\,b} {a\,+\,b} \)
	D. \(\frac {b\,-\,a} {a\,+\,b} \)
	E. \(\frac {-a\,+\,b} {a\,-\,b} \)
	F. \(\frac {a\,+\,b} {a\,-\,b} \)
	G. 0

[ 5921 - op net sinds 30.6.10-(E)-30.10.2023 ]

Translation in E N G L I S H

	B. − 2ab
$\frac{(a-b)^2}{a^2-b^2}$ equals	A. 1
	C. \(\frac {a\,-\,b} {a\,+\,b} \)
	D. \(\frac {b\,-\,a} {a\,+\,b} \)
	E. \(\frac {-a\,+\,b} {a\,-\,b} \)
	F. \(\frac {a\,+\,b} {a\,-\,b} \)
	G. 0

Oplossing - Solution

$\frac{(a-b)^2}{a^2-b^2}=\frac{(a-b)(a-b)}{(a-b)(a+b)}=\frac{a-b}{a+b}$