Als je   x3 − 8
ontbind in factoren,
is één van de factoren
A.   x2 + 2x + 4
B.   x2 − 2x + 4
C.     x + 2
D.   x2 − 4x + 4
E.   x2 + 4x + 4
                 

[ 3-3382 - op net sinds 30.8.06-7.1.12-(E)-29.10.2023 ]

Translation in   E N G L I S H

Factoring the polynomial
x3 − 8
one of the factors is 		A.   x2 + 2x + 4
B.   x2 − 2x + 4
C.     x + 2
D.   x2 − 4x + 4
E.   x2 + 4x + 4

Oplossing - Solution

a³ − b³ = (a − b)(a² + ab + b²)
x³ − 2³ = (x − 2)(x² + 2x + 4)